Validate decimal numbers in JavaScript - IsNumeric()

What's the cleanest, most effective way to validate decimal numbers in JavaScript?

Bonus points for:

  1. Clarity. Solution should be clean and simple.
  2. Cross-platform.

Test cases:

01. IsNumeric('-1')
   => true 02. IsNumeric('-1.5')
 => true 03. IsNumeric('0')
    => true 04. IsNumeric('0.42')
 => true 05. IsNumeric('.42')
  => true 06. IsNumeric('99,999')  => false 07. IsNumeric('0x89f')   => false 08. IsNumeric('#abcdef') => false 09. IsNumeric('1.2.3')   => false 10. IsNumeric('')
 => false 11. IsNumeric('blah')
 => false 
Text Copied From
on : Wed, Aug 20, 2008 Views : 1395700

Accepted Answer

@Joel's answer is pretty close, but it will fail in the following cases:

// Whitespace strings: IsNumeric(' ') == true;
 IsNumeric('\t\t') == true;
 IsNumeric('\n\r') == true;
// Number literals: IsNumeric(-1) == false;
 IsNumeric(0) == false;
 IsNumeric(1.1) == false;
 IsNumeric(8e5) == false;

Some time ago I had to implement an IsNumeric function, to find out if a variable contained a numeric value, regardless of its type, it could be a String containing a numeric value (I had to consider also exponential notation, etc.), a Number object, virtually anything could be passed to that function, I couldn't make any type assumptions, taking care of type coercion (eg. +true == 1;
but true shouldn't be considered as numeric).

I think is worth sharing this set of +30 unit tests (old link) made to numerous function implementations, and also share the one that passes all my tests:

function isNumeric(n) 
   return !isNaN(parseFloat(n)) &

P.S. isNaN & isFinite have a confusing behavior due to forced conversion to number. In ES6, Number.isNaN & Number.isFinite would fix these issues. Keep that in mind when using them.

Update : Here's how jQuery does it now (2.2-stable) :

function( obj ) 

  var realStringObj = obj &

  return !jQuery.isArray( obj ) &
 ( realStringObj - parseFloat( realStringObj ) + 1 ) >= 0;

Update : Angular 4.3 :

function isNumeric(value: any): boolean 
   return !isNaN(value - parseFloat(value));
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on : Wed, Dec 02, 2009

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